If one choice has m options and the next has n, together they have m × n outcomes. Everything else is built on this.
Step 1: Let's Learn
Read it, or press Listen and follow the words.
Factorials
n! multiplies every whole number from n down to 1. Five books arrange on a shelf in 5! = 120 ways.
Permutations
A permutation counts arrangements, where order matters. nPr = n! ÷ (n − r)!.
Combinations
A combination counts selections, where order does not matter. nCr = n! ÷ (r!(n − r)!).
The link
A combination is a permutation with the r! orderings divided out, so nCr is always smaller than nPr.
How to decide
Ask whether swapping two chosen items produces a different outcome. A president and a vice-president, yes. A committee of two, no.
Does order matter?
A permutation counts arrangements, where order matters. A combination counts selections, where it does not. Deciding which question you are answering is the whole difficulty; the formulas are then mechanical.
The two formulas
Permutations of r from n: n!/(n − r)!. Combinations: n!/(r!(n − r)!). The extra r! divides out the orderings you no longer wish to distinguish, which is exactly the difference between the two questions.
Factorials count arrangements
n! is the number of ways to order n distinct objects: n choices for first, n − 1 for second, and so on. And 0! = 1, because there is exactly one way to arrange nothing — a convention that keeps the formulas working.
A quick test
Would swapping two of your chosen items give a different outcome? A committee of Ana and Ben is the same as Ben and Ana, so it is a combination. First and second place is not, so it is a permutation.
Step 2: Try It Yourself
Tap and try it out.
Arrangements has the most. It has 10 more than Selections.
Step 3: Watch an Example
One step at a time.
Watch Ines Pick a Committee
From 6 students, Ines needs a committee of 3.
- Step 1
Swapping two committee members changes nothing, so order does not matter.
Step 4: Your Turn
Practice makes it stick.
The Shelf
Problem 1 of 2
How many ways can 4 books be arranged in a row?
The Pizza
Problem 2 of 2
How many ways can 2 toppings be chosen from 5, when order does not matter?
Count the Ways
1 of 8
What is 5!?
2 of 8
What is 6C2?
3 of 8
What is 5P2?
4 of 8
A menu has 3 starters and 4 mains. How many two-course meals?
5 of 8
What is 7C7?
6 of 8
How many 3-digit codes use digits 0 to 9 with repeats allowed?
7 of 8
Sort each situation by whether order matters.
Tap something to move it.
- Empty
- Empty
8 of 8
What is 4C2?
Step 5: Quick Check
Show what you know.
Question 1 of 2
How many ways can 3 books be arranged in a row?
Question 2 of 2
Choosing a committee of 3 from 10 uses which count?
What You Learned
- Multiply the options at each stage to count outcomes.
- Permutations count arrangements; combinations count selections.
- nCr is nPr with the r! orderings divided out, so it is always smaller.