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Math · Trigonometry

Chapter 7: The Law of Sines and Cosines

Area of Any Triangle

When you cannot see the height.

Lesson
3
Time
About 21 minutes
0 of 12 done

Step 1: Let's Learn

Read it, or press Listen and follow the words.

The familiar ½ × base × height needs a height, and a slanted triangle rarely hands you one.

The sine formula

Area = ½ab sin C, where a and b are two sides and C is the angle between them.

Where it comes from

The height dropped from one vertex is b sin C. Substituting that into ½ × base × height gives the formula directly.

The angle must be between

C has to be the included angle. Any other angle gives the wrong height and the wrong area.

When you have three sides

With no angle at all, use Heron’s formula. Let s = (a + b + c) ÷ 2, then area = √(s(s−a)(s−b)(s−c)).

Area when you cannot see the height

Area = ½ab sin C uses two sides and the angle between them. It comes from ½ × base × height, with the height written as a sin C — trigonometry supplying the height you cannot measure directly.

The angle must be included

The angle in the formula must be the one between the two sides used. Substituting a non-included angle gives an answer that is wrong without looking wrong, which makes it a dangerous error.

Heron's formula for three sides

With all three sides and no angle, Heron's formula gives the area from the semi-perimeter. It needs no trigonometry at all and is the right tool when the SSS case arises.

Where it is used

Surveying irregular land, computing forces on triangular structures, and any graphics application that shades triangles. Triangles are the universal building block of computational geometry, and their area is computed constantly.

Step 2: Try It Yourself

Tap and try it out.

Check the formula on a right triangle: with C = 90°, sin C is 1 and ½ab is the ordinary area.
adjacent = 6opposite = 4hyp = 7.2133.69°
  • sin — opposite over hypotenuse0.55
  • cos — adjacent over hypotenuse0.83
  • tan — opposite over adjacent0.67
  • The marked angle33.69°

The hypotenuse is not given. It comes from 6² + 4² = 52, whose square root is 7.21.

Step 3: Watch an Example

One step at a time.

Watch Ines Find a Field Area

A triangular field has sides of 40 m and 30 m with an angle of 30° between them.

  1. Step 1

    The 30° sits between the two known sides, so the sine formula applies.

Step 4: Your Turn

Practice makes it stick.

The Garden

Problem 1 of 2

Sides 10 and 12 with an included angle of 30°. What is the area?

The Three Sides

Problem 2 of 2

A triangle has sides 3, 4 and 5. What is s in Heron’s formula?

Area Without a Height

1 of 8

Sides 8 and 10, included angle 30°. Area?

2 of 8

Sides 6 and 6, included angle 90°. Area?

3 of 8

Sides 3, 4, 5 with s = 6. What is the Heron area?

4 of 8

Sides 5, 5, 6. What is s?

5 of 8

Sides 5, 5, 6 with s = 8. What is the area?

6 of 8

Sides 20 and 14, included angle 90°. Area?

7 of 8

Sort each situation by which formula fits.

Tap something to move it.

  • Empty
  • Empty

8 of 8

Sides 12 and 5, included angle 90°. Area?

Step 5: Quick Check

Show what you know.

Question 1 of 2

Sides 10 and 4, included angle 30°. What is the area?

Question 2 of 2

The angle in ½ab sin C must be which one?

What You Learned

  • Area = ½ab sin C, where C is the angle between the two sides.
  • With three sides and no angle, use Heron’s formula.
  • A right angle makes sin C equal 1, recovering the familiar ½ × base × height.