Cogito
Calculus · Chapter 5 · Lesson 3
Linear Approximation
Use the tangent line instead of the curve.
12 problems · about 21 minutes · CHA-3.F
Figure — use these to answer the problems
- Point(4, 2)
- Slope of the tangent0.25
Warm Up
Straightforward practice. Get the method working first.
5 problemsL(x) = 4 + 0.5(x − 16). What is L(16.4)?
AnswerWhy does the estimate worsen far from the base point?
- The curve bends away from its tangent line.
- Rounding errors accumulate.
L(x) = 3 + 2(x − 1). What is L(1.5)?
Answerf(9) = 3 and f′(9) = 1/6. Estimate f(9.6).
Answerf(x) = √x. What is f(25)?
Answer
Build It Up
The same ideas with more to keep track of.
3 problemsA curve is concave up. Is the estimate high or low? 1 high, 2 low.
AnswerL(x) = 2 + 0.25(x − 4). What is L(4)?
Answerdy = f′(x) dx. With f′(x) = 6 and dx = 0.5, what is dy?
Answer
Stretch Yourself
Mixed problems. Work out what kind of question it is before you start.
4 problemsWhich choices make a linear approximation more accurate?
- Choosing a base point close to the target
- A curve that is nearly straight near the point
- Moving far from the base point
- A sharply bending curve
- Tick every box that applies.
L(x) = 5 + 3(x − 2). What is L(2.1)?
AnswerThe Estimate
L(x) = 2 + 0.25(x − 4). What is L(4.2)?
AnswerThe Direction
A curve is concave down. Is the tangent estimate too high or too low? 1 high, 2 low.
Answer