Cogito
Calculus · Chapter 6 · Lesson 2
The Second Derivative and Concavity
How the slope itself is changing.
12 problems · about 22 minutes · FUN-4.A
Figure — use these to answer the problems
- Point(0, 0)
- Slope of the tangent-3
Warm Up
Straightforward practice. Get the method working first.
5 problemsf′(4) = 0 and f″(4) = −3. Max or min? 1 max, 2 min.
AnswerWhat does an inflection point require?
- The second derivative must change sign.
- The second derivative must equal zero.
f″(3) = 4. Concave up or down? 1 up, 2 down.
Answerf′(5) = 0 and f″(5) = 2. Max or min? 1 max, 2 min.
Answerf(x) = x², so f″(x) = 2. Concave up or down everywhere? 1 up, 2 down.
Answer
Build It Up
The same ideas with more to keep track of.
3 problemsf(x) = x³ − 3x, so f″(x) = 6x. What is f″(−2)?
Answerf′(1) = 0 and f″(1) = 0. Is the test conclusive? 1 for yes, 0 for no.
AnswerHow many inflection points does a cubic have?
Answer
Stretch Yourself
Mixed problems. Work out what kind of question it is before you start.
4 problemsSort each sign of the second derivative by what it means.
Write each item under the heading it belongs to: f″ = 3 · f″ = −7 · The slope is increasing · The slope is decreasing
Concave up
Concave down
f(x) = x⁴, so f″(x) = 12x². What is f″(2)?
AnswerThe Test
f′(2) = 0 and f″(2) = −5. Is x = 2 a maximum or minimum? 1 max, 2 min.
AnswerThe Inflection
f″(x) = 6x. At which x is there an inflection point?
Answer