Cogito
AP Precalculus · Chapter 3 · Lesson 3
Slant Asymptotes and Rational Graphs
When the end behaviour is a line.
12 problems · about 21 minutes · AP Precalculus 1.12
Figure — use these to answer the problems
- Point(3, 0.33)
Warm Up
Straightforward practice. Get the method working first.
5 problemsNumerator degree 3, denominator degree 2. Slant asymptote? 1 yes, 0 no.
AnswerHow do you find a slant asymptote?
- Divide, and take the polynomial part of the quotient.
- Take the ratio of the leading coefficients.
Numerator degree 2, denominator degree 1. Slant asymptote? 1 yes, 0 no.
AnswerNumerator degree 1, denominator degree 1. Slant asymptote? 1 yes, 0 no.
AnswerNumerator degree 4, denominator degree 2. Slant asymptote? 1 yes, 0 no.
Answer
Build It Up
The same ideas with more to keep track of.
3 problemsCan a rational function have both a horizontal and a slant asymptote? 1 yes, 0 no.
Answerf(x) = (6x + 1) ÷ (2x − 5). Horizontal asymptote value?
Answerf(x) = 5 ÷ (x + 3). Vertical asymptote at which x?
Answer
Stretch Yourself
Mixed problems. Work out what kind of question it is before you start.
4 problemsSort each degree comparison by the end behaviour it gives.
Write each item under the heading it belongs to: Equal degrees · Numerator degree smaller · Numerator exactly one higher · Degree 3 over degree 2
Horizontal asymptote
Slant asymptote
f(x) = (x + 2) ÷ (x² + 1). Horizontal asymptote value?
AnswerThe Degrees
Numerator degree 3, denominator degree 2. Slant asymptote? 1 yes, 0 no.
AnswerThe Vertical
f(x) = (x² + 1) ÷ (x − 1). At which x is the vertical asymptote?
Answer