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Math · AP Calculus AB

Chapter 4: Contextual Applications

Linearisation and Differentials

Using the tangent line as the function.

Lesson
2
Time
About 21 minutes
0 of 12 done

Step 1: Let's Learn

Read it, or press Listen and follow the words.

Near the point of tangency a curve and its tangent are almost identical, and the line is far easier to evaluate.

The formula

L(x) = f(a) + f′(a)(x − a). It is the tangent line at a, used as a stand-in for f.

Choosing the base point

Pick an a nearby where the function is exactly known. For √4.1, take a = 4, where the value is exactly 2.

Which way it errs

A concave-down curve sits below its tangent, so the estimate is too high. Concave up gives an underestimate.

The exam asks for the direction

Free-response questions routinely ask whether an approximation is an over- or underestimate. The answer is the sign of f double prime.

Differentials

dy = f′(x) dx estimates the change in the function for a small change in input.

The tangent line as a stand-in

L(x) = f(a) + f′(a)(x − a) approximates f near a. It is simply the tangent line, used to estimate values of a function that is awkward to evaluate directly.

Over or under, decided by concavity

If f is concave up, the tangent lies below the curve and the approximation underestimates. Concave down means it overestimates. The exam asks for this justification, and it comes from the sign of f″.

Differentials

dy = f′(x)dx estimates the change in output from a small change in input. It is the same idea in different notation, and it is how error propagation is computed in the sciences.

The approximation degrades with distance

It is excellent close to a and worsens as you move away, at a rate governed by the second derivative. Using a linearisation far from its base point is a misuse, not merely an inaccuracy.

Step 2: Try It Yourself

Tap and try it out.

See how tightly the tangent hugs the curve near the point, and how fast it drifts away.
-8-8-6-6-4-4-2-222446688
y = 1√x + 0
  • Point(4, 2)
  • Slope of the tangent0.25

Step 3: Watch an Example

One step at a time.

Watch Kofi Estimate a Root

Kofi approximates √4.1 using a tangent line.

  1. Step 1

    He takes f(x) = √x and the nearby exact point a = 4, where f(4) = 2.

Step 4: Your Turn

Practice makes it stick.

The Estimate

Problem 1 of 2

L(x) = 2 + 0.25(x − 4). What is L(4.2)?

The Direction

Problem 2 of 2

A curve is concave down. Is the tangent estimate an over- or underestimate? 1 over, 2 under.

Approximate With a Line

1 of 8

L(x) = 3 + 2(x − 1). What is L(1.5)?

2 of 8

f(9) = 3 and f′(9) = 1/6. Estimate f(9.6).

3 of 8

A curve is concave up. Over- or underestimate? 1 over, 2 under.

4 of 8

L(x) = 2 + 0.25(x − 4). What is L(4)?

5 of 8

dy = f′(x) dx with f′(x) = 6 and dx = 0.5. What is dy?

6 of 8

Which sign of f double prime gives an overestimate? 1 positive, 2 negative.

7 of 8

Which choices improve a linear approximation?

8 of 8

L(x) = 5 + 3(x − 2). What is L(2.1)?

Step 5: Quick Check

Show what you know.

Question 1 of 2

L(x) = 4 + 0.5(x − 16). What is L(16.4)?

Question 2 of 2

What determines whether an approximation is an over- or underestimate?

What You Learned

  • L(x) = f(a) + f′(a)(x − a) uses the tangent as a stand-in.
  • Concave down overestimates; concave up underestimates.
  • Accuracy falls away as you move from the base point.