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Math · Integrated Math 1

Chapter 2: Linear Functions

Modelling with Linear Functions

Turning a situation into an equation.

Lesson
3
Time
About 21 minutes
0 of 12 done

Step 1: Let's Learn

Read it, or press Listen and follow the words.

A linear model fits a situation with a constant rate of change: a fixed fee plus a per-unit charge.

What each parameter means

The slope is the per-unit rate and the intercept is the starting amount, before any units are used.

Building one

Identify the fixed part and the rate, then write y = rate × x + fixed.

Context restricts the domain

A model of tickets sold makes no sense at x = −3 or x = 2.5. State the values that actually apply.

Careful beyond the data

A model fitted to one range may fail outside it. A growth rate measured over a month rarely holds for a decade.

Answer in words

A modelling answer is a sentence with units, not a bare number. "It costs $47" beats "47".

A rate and a starting value

Most linear situations have a fixed amount plus a per-unit charge — a joining fee plus a monthly rate. Recognising that structure gives you the equation almost immediately.

Say what m and b mean

For a taxi at £3 plus £2 per mile, the slope is the per-mile rate and the intercept the fixed charge. Naming them in context is usually what a modelling question is actually asking for.

The situation restricts the domain

Negative miles and fractional people are mathematically permitted and contextually meaningless. Stating the sensible domain is part of a complete model rather than an optional refinement.

Models have a range of validity

A linear model fitted to a few data points may fail badly outside them. Predicting far beyond the observed range assumes a straight line continues, which nothing in the data supports.

Step 2: Try It Yourself

Tap and try it out.

Set the intercept to a fixed fee and the slope to a per-unit charge. The line is the whole cost model.
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y = 3x + 2

The slope is 3: for every 1 across, the line goes 3 up.

Step 3: Watch an Example

One step at a time.

Watch Kofi Model a Phone Plan

A plan costs $20 a month plus $0.10 per minute.

  1. Step 1

    The $20 is charged regardless of use, so it is the fixed part.

Step 4: Your Turn

Practice makes it stick.

The Plan

Problem 1 of 2

C = 0.10m + 20. What is the cost for 300 minutes, in dollars?

dollars

The Fee

Problem 2 of 2

A gym charges $30 to join plus $15 a month. Cost after 6 months, in dollars?

dollars

Build the Model

1 of 8

C = 5x + 12. What is the fixed amount?

2 of 8

C = 5x + 12. What is the rate per unit?

3 of 8

C = 5x + 12 at x = 8. What is C?

4 of 8

$25 joining fee plus $10 a month. Cost after 4 months, in dollars?

5 of 8

A tank holds 100 L and drains 4 L a minute. Litres after 10 minutes?

6 of 8

For a model counting tickets sold, is x = 2.5 in the domain? 1 yes, 0 no.

7 of 8

Put the modelling steps in order.

  1. 1Identify the rate per unit.
  2. 2Write the equation combining both.
  3. 3State which input values make sense.
  4. 4Identify the fixed starting amount.

8 of 8

C = 2x + 40 at x = 15. What is C?

Step 5: Quick Check

Show what you know.

Question 1 of 2

$40 fee plus $6 an hour. Cost for 5 hours, in dollars?

Question 2 of 2

In a cost model, what does the y-intercept represent?

What You Learned

  • A linear model is rate times units plus a fixed amount.
  • The slope is the per-unit rate; the intercept is the starting value.
  • Context restricts which inputs make sense.