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Math · Integrated Math 2

Chapter 2: Solving Quadratic Equations

Solving by Factoring

A product is zero only when a factor is.

Lesson
1
Time
About 21 minutes
0 of 12 done

Step 1: Let's Learn

Read it, or press Listen and follow the words.

If a product is zero, at least one factor is zero. This is what turns a factored quadratic into two simple equations.

The right side must be zero

The property applies only to zero. From (x − 2)(x − 3) = 6 you cannot conclude anything about the factors.

Factoring a trinomial

For x² + bx + c, find two numbers multiplying to c and adding to b.

Difference of squares

a² − b² factors as (a + b)(a − b). Recognising it saves the whole search.

Common factor first

Always take out a common factor before anything else. It makes what remains far easier to factor.

It does not always work

Many quadratics do not factor over the integers. Those need the formula, which comes next.

The zero product property

If a product equals zero, at least one factor must be zero. That is why factoring solves equations, and it is why the equation must first be arranged with zero on one side.

Set it equal to zero first

Factoring x² + 5x = 6 and setting each factor to 6 is wrong, because the zero product property applies only to zero. Rearranging to x² + 5x − 6 = 0 is a mandatory first step.

Take out common factors first

For 2x² + 10x + 12, extract the 2 before factoring further. It keeps the remaining numbers small, and it is the step most often skipped.

Not everything factors

x² + x + 1 has no factorisation over the integers. That is not a failure of technique — the roots are irrational or complex. Knowing when to stop and use the formula saves considerable time.

Step 2: Try It Yourself

Tap and try it out.

The roots are where the curve meets the axis. Factoring finds those crossings algebraically.
-8-8-6-6-4-4-2-222446688
y = 1x² − 5x + 6

Step 3: Watch an Example

One step at a time.

Watch Diego Factor and Solve

Diego solves x² − 5x + 6 = 0.

  1. Step 1

    He needs two numbers multiplying to 6 and adding to −5.

Step 4: Your Turn

Practice makes it stick.

The Factors

Problem 1 of 2

(x − 4)(x + 2) = 0. What is the positive solution?

The Trinomial

Problem 2 of 2

x² − 5x + 6 = 0. What is the larger solution?

Factor and Solve

1 of 8

(x − 7)(x + 1) = 0. Larger solution?

2 of 8

x² − 9 = 0. Positive solution?

3 of 8

x² + 5x + 6 = 0. Larger solution?

4 of 8

x² − 7x = 0. Non-zero solution?

5 of 8

x² − 16 = 0. Positive solution?

6 of 8

x² − 4x + 4 = 0. What is the repeated solution?

7 of 8

Which expressions are a difference of squares?

8 of 8

x² − 8x + 15 = 0. Larger solution?

Step 5: Quick Check

Show what you know.

Question 1 of 2

x² − 6x + 8 = 0. What is the larger solution?

Question 2 of 2

Why must the equation equal zero before factoring helps?

What You Learned

  • A product is zero only when a factor is zero.
  • Rearrange to equal zero, then factor.
  • Take out a common factor first and watch for a difference of squares.