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Math · Integrated Math 2

Chapter 8: Probability

Conditional Probability

Given that something already happened.

Lesson
2
Time
About 21 minutes
0 of 12 done

Step 1: Let's Learn

Read it, or press Listen and follow the words.

A conditional probability asks how likely A is given that B has happened.

The formula

P(A given B) = P(A and B) ÷ P(B). The condition shrinks the world to just B.

From a table

Condition on a row or column by using that total as the denominator instead of the grand total.

Order matters

P(A given B) and P(B given A) are different questions with different denominators, and usually different answers.

A test for independence

If P(A given B) equals P(A), the condition changed nothing and the events are independent.

Why it matters

Most people who are ill test positive, yet most people testing positive may still be well when the illness is rare. Swapping the two is a costly error.

Conditioning changes the denominator

P(A | B) restricts attention to outcomes where B occurred, so you divide by P(B) rather than by the whole. That change of denominator is the entire content of conditioning.

The order is not reversible

P(A | B) and P(B | A) are generally very different. The chance of a positive test given illness is not the chance of illness given a positive test, and confusing them has real consequences.

Base rates dominate rare events

A highly accurate test for a rare condition still produces mostly false positives, because there are so many more unaffected people to be wrong about. Ignoring the base rate is the classic failure.

Tree diagrams organise the conditioning

Each branch carries a conditional probability and multiplying along a path gives the joint probability. Drawing the tree turns a confusing problem into arithmetic.

Step 2: Try It Yourself

Tap and try it out.

Conditioning means using one bar as the new total rather than the sum of them all.
Group A12
Group B8

Group A has the most. It has 4 more than Group B.

Step 3: Watch an Example

One step at a time.

Watch Sana Condition on a Row

Of 100 students, 60 play sport, and 45 of those also play music.

  1. Step 1

    The condition is playing sport, so the world shrinks from 100 to 60.

Step 4: Your Turn

Practice makes it stick.

The Condition

Problem 1 of 2

P(A and B) = 0.2 and P(B) = 0.5. What is P(A given B)?

The Table

Problem 2 of 2

Of 60 sport players, 45 play music. What is P(music given sport)?

Given That

1 of 8

P(A and B) = 0.3, P(B) = 0.6. P(A given B)?

2 of 8

P(A and B) = 0.12, P(B) = 0.4. P(A given B)?

3 of 8

18 of 24 in a group have a trait. P(trait given the group)?

4 of 8

P(A given B) = P(A). Independent? 1 yes, 0 no.

5 of 8

A die shows an even number. P(it is a 6), to three decimal places?

6 of 8

Is P(A given B) always equal to P(B given A)? 1 yes, 0 no.

7 of 8

Put the conditional probability method in order.

  1. 1Use that event as the new total.
  2. 2Count how many of those also satisfy the other event.
  3. 3Divide to get the conditional probability.
  4. 4Identify which event is the condition.

8 of 8

P(A and B) = 0.35, P(B) = 0.7. P(A given B)?

Step 5: Quick Check

Show what you know.

Question 1 of 2

P(A and B) = 0.18, P(B) = 0.6. What is P(A given B)?

Question 2 of 2

What does conditioning on B do?

What You Learned

  • P(A given B) = P(A and B) ÷ P(B).
  • Conditioning replaces the sample space with a slice of it.
  • If conditioning changes nothing, the events are independent.