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Math · Integrated Math 2

Chapter 8: Probability

Counting and Fair Decisions

Counting outcomes, and using probability to decide.

Lesson
3
Time
About 21 minutes
0 of 12 done

Step 1: Let's Learn

Read it, or press Listen and follow the words.

If one stage has m options and the next has n, together they have m × n outcomes.

Permutations

A permutation counts arrangements, where order matters. Three books arrange in 3! = 6 ways.

Combinations

A combination counts selections, where order does not matter. It is a permutation with the orderings divided out.

How to choose

Ask whether swapping two chosen items changes the outcome. A president and vice-president, yes; a committee of two, no.

Expected value

Multiply each outcome by its probability and add. It is the long-run average result.

Fair games

A game is fair when the expected gain is zero, once the cost of playing is subtracted.

The multiplication principle

If one stage has m options and the next has n, there are mn outcomes. Nearly all counting reduces to this applied repeatedly, and a small tree confirms it.

Order matters, or it does not

Permutations count arrangements, combinations count selections. Ask whether swapping two chosen items changes the outcome; if not, divide out the orderings and you have a combination.

Expected value judges a decision

Multiply each outcome by its probability and sum. It is the long-run average, and comparing expected values is how two uncertain options are compared on the same footing.

Expected value ignores risk

A bet with positive expected value that could ruin you is still a poor decision, and insurance with negative expected value can still be rational. Expected value is one input to a decision, not the decision.

Step 2: Try It Yourself

Tap and try it out.

Choosing 2 from 5: twenty arrangements but only ten selections, because order doubles the count.
Arrangements20
Selections10

Arrangements has the most. It has 10 more than Selections.

Step 3: Watch an Example

One step at a time.

Watch Kofi Judge a Game

A game costs $2 and pays $10 with probability 0.1, nothing otherwise.

  1. Step 1

    The expected payout is 10 × 0.1 + 0 × 0.9 = $1.

Step 4: Your Turn

Practice makes it stick.

The Committee

Problem 1 of 2

How many ways to choose 3 people from 6, when order does not matter?

The Game

Problem 2 of 2

Pays $10 with probability 0.1, costs $2. What is the expected gain, in dollars?

dollars

Count and Decide

1 of 8

What is 4 factorial?

2 of 8

What is 5C2?

3 of 8

What is 5P2?

4 of 8

3 shirts and 4 trousers. How many outfits?

5 of 8

Pays $20 with probability 0.25. Expected payout in dollars?

6 of 8

Expected payout $5, cost $5. Expected gain in dollars?

7 of 8

Sort each situation by whether order matters.

Tap something to move it.

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8 of 8

What is 6C2?

Step 5: Quick Check

Show what you know.

Question 1 of 2

How many ways can 4 books be arranged in a row?

Question 2 of 2

What makes a game fair?

What You Learned

  • Multiply the options at each stage to count outcomes.
  • Permutations count arrangements; combinations count selections.
  • A fair game has an expected gain of zero.