Cogito
Multivariable Calculus · Chapter 5 · Lesson 3
Gradient Fields and Normal Lines
The gradient of a whole surface, drawn everywhere at once.
12 problems · about 22 minutes · N-VM.A.1, G-GPE.A.1
Figure — use these to answer the problems
- Released from(1, 1)
Warm Up
Straightforward practice. Get the method working first.
5 problemsf = x² + y² at (6, 8). What is the magnitude of ∇f?
AnswerWhy does the gradient work as a normal vector to a level curve?
- Moving along the curve changes nothing, so the gradient must be perpendicular to it.
- Because it is the longest vector available.
f = x² + y². What is the x-component of ∇f at (5, 2)?
AnswerIs the gradient perpendicular to the level curve? 1 yes, 0 no.
Answerf = 3x + 4y. What is the magnitude of ∇f?
Answer
Build It Up
The same ideas with more to keep track of.
3 problemsThe tangent line 6(x − 3) + 8(y − 4) = 0 expands to 6x + 8y = k. What is k?
AnswerOn a sphere, does the gradient point along the radius? 1 yes, 0 no.
Answerf = xy. What is the y-component of ∇f at (4, 9)?
Answer
Stretch Yourself
Mixed problems. Work out what kind of question it is before you start.
4 problemsOrder the steps for finding a tangent line to a level curve.
Write 1 to 4 in the boxes to put these in order.
- Write the curve as a level curve of some f
- Compute the gradient of f
- Evaluate the gradient at the point
- Use it as the normal in the line equation
f = 7. What is the magnitude of ∇f?
AnswerThe Sphere
On x² + y² + z² = 14 at (1, 2, 3), the gradient is ⟨2x, 2y, 2z⟩. What is its z-component there?
AnswerThe Normal
A level curve has normal ⟨4, 3⟩ at a point. What is the magnitude of that normal?
Answer